REVIEW EXAM


STATES AS VECTORS:




OBSERVABLES AS OPERATORS

Recall for all operators: Oop|a> = |a'>

and for linear operators: Oop ( |a> + |b> ) = Oop|a> + Oop|b>

unit operator: 1op|a> =|a> for all states

Matrices have these properties when applied to vector (column matrix). Some operators are represented by square matrices in a particular basis.

Note: <b|Oop|a> means <b| ( Oop |a> )

<b|Oop|a> = ( <b| Oop*T ) |a>

Ex//

|a> =

0   

1   


|b> =

i   

0   


Oop =

1     0                                                             

i     1                                                             


If Oop corresponds to an observable, then Oop*T = Oop . Such an operator is Hermitian.

EIGENSTATES AND EIGENVALUES

Oop|n> = On |n> where On is a number

If operator is represented by matrix, you get a matrix eigenvalue problem.

Ex//

Eigenvalues of operator represented by

5      2     1       

3      3     3       

1      6     2       


Suppose we found all eigenstates |i> of an obsevable, with eigenvalues Oi.

Suppose the state of our particle is |a>.

The probability that the the observable is found to have value Oi is |<i|a>|2.

The probability that the observable is found to have any value is

true for any state vector |a> and any complete set {|i>}.

We can write any state vector as a combo of these states:

Check that <a|a> =1.

COMMUTATOR

[Oop,Qop] =OopQop - QopOop

or OopQop = QopOop +[Oop,Qop]

Ex// Find <x1|popxop|p1> (a number depending on the specific position x1 and the specific momentum p1).

Ex// Find commutator of Oop above and

Qop =

2     1                                                               

1     1