REVIEW EXAM
STATES AS VECTORS:
- Each physical state corresponds to a state vector |a>
("ket"). Different physical states correspond to different
vectors and vice versa. "a" is a label.
- State vectors obey the properties of vectors, see list p98
for addition and mult by const. Also
- If |a> and |b> are possible state vectors, then A|a>
+B|b> is also a possible state vector.
- A vector space must have a norm or "length."
- "Inner product" of state vector with itself, written
<a|a>, gives the norm.
- <a|a> = 1. Normalization condition.
- Mathematical properties of inner product
- it is a (complex) number
- see list p99, including <a|b> = <b|a>*
- Physical meaning of inner product <b|a>:
|<b|a>|2
= |<a|b>|2 = probability of finding particle in state
|a> to be in state |b> (or vice versa).
- psi(x) = <x|a>
|psi(x)|2 = |<x|a>|2 = probability
of finding particle in state |a> to be in state |x> --
in other words the probability density of finding particle in
state |a> to be at position x.
- phi(p) = <p|a>
|phi(p)|2 = |<p|a>|2 = probability
of finding particle in state |a> to be in state |p> --
in other words the probability density of finding particle in
state |a> to have momentum p.
- an = <En|a>
|an|2 = |<En|a>|2 = probability
of finding particle in state |a> to be in state |En> --
in other words the probability of finding particle in state |a>
to have energy En.
- The set of all eigenstates of an observable
form a complete orthonormal set of states, {|ai>}.*
- ortho- means orthogonal:
If |an> and |am> are
eigenstates corresponding to different eigenvalues, then <an|am>=0.
- Ex/ Suppose |E1> is the ground state and |E2> is first
excited state.
The probability that a particle in the ground
state would be found in the first excited state is zero.
|<E1|E2>|2
= 0, so <E1|E2> = 0.
- -normal means normalized: <ai|ai> = 1 for all
i.
- complete means it can be used as a basis for a representation:
Any state vector can be written as a linear combo of these basis
vectors:
- Ex/ Suppose |a> cannot be written as linear combo of energy
eigenstates. Suppose it is
|a> = (3)-1/2 |E1> + (3) -1/2
|E2> + (3) -1/2 |not an energy eigenstate>,
then with prob
1/3 an energy measurement will result in "not an energy"!!
Can't be.
- There are many observables whose eigenstates we can use as
basis vectors, so there are many representations of a state
vector:
- Position representation:
- where |x> is an eigenstate of position - state of definite
position, x.
- Momentum representation:
- where |p> is an eigenstate of momentum - state of definite
momentum, p.
- Energy representation:
- where |En> is an eigenstate of energy - state of definite
energy En.
OBSERVABLES AS OPERATORS
Recall for all operators: Oop|a> = |a'>
and for linear operators: Oop ( |a> + |b> ) = Oop|a>
+ Oop|b>
unit operator: 1op|a> =|a> for all states
Matrices have these properties when applied to vector (column
matrix). Some operators are represented by square
matrices in a particular basis.
Note: <b|Oop|a> means <b| ( Oop |a> )
<b|Oop|a> = ( <b| Oop*T ) |a>
Ex//
|a> =
0
1
|b> =
i
0
Oop =
1 0
i 1
If Oop corresponds to an observable, then Oop*T
= Oop . Such an operator is Hermitian.
EIGENSTATES AND EIGENVALUES
Oop|n> = On |n> where On is a number
If operator is represented by matrix, you get a matrix eigenvalue
problem.
Ex//
Eigenvalues of operator represented by
5 2 1
3 3 3
1 6 2
Suppose we found all eigenstates |i> of an obsevable, with
eigenvalues Oi.
Suppose the state of our particle is |a>.
The probability that the the observable is found to have value
Oi is |<i|a>|2.
The probability that the observable is found to have any
value is
true for any state vector |a> and any complete set {|i>}.
We can write any state vector as a combo of these states:
Check that <a|a> =1.
COMMUTATOR
[Oop,Qop] =OopQop - QopOop
or OopQop = QopOop +[Oop,Qop]
Ex// Find <x1|popxop|p1> (a number depending on
the specific position x1 and the specific momentum p1).
Ex// Find commutator of Oop above and
Qop =
2 1
1 1